Fluid Mechanics Cheat Sheet

The equations of an introductory fluid mechanics course on one page: properties and viscosity, hydrostatic pressure and forces on surfaces, buoyancy, continuity, Bernoulli and the energy equation, momentum, Reynolds number and pipe friction losses. Each line lists its variables and SI units.

What’s on the sheet

Fluid properties

Fluid properties: formula, then every variable with its unit
QuantityFormulaVariables and units
Density, specific weight, specific gravityρ = m/V; γ = ρ·g; SG = ρ/ρwaterρ (kg/m³); γ (N/m³); SG dimensionless
Newtonian shear stressτ = μ·du/dyμ dynamic viscosity (Pa·s); du/dy velocity gradient (1/s)
Kinematic viscosityν = μ/ρν (m²/s); water at 20 °C is about 1.0 × 10−6 m²/s

Hydrostatics

Hydrostatics: formula, then every variable with its unit
QuantityFormulaVariables and units
Pressure with depthP = P0 + ρ·g·hh depth below the free surface (m); P (Pa)
Gauge and absolute pressurePabs = Pgauge + PatmPatm = 101.325 kPa standard
Force on a submerged planeF = ρ·g·hc·Ahc depth of the area’s centroid (m); A area (m²)
Centre of pressureyp = yc + Ic/(yc·A)y measured along the plate from the surface (m); Ic centroidal (m4)
Buoyancy (Archimedes)FB = ρfluid·g·VdisplacedV displaced volume (m³)

Conservation laws

Conservation laws: formula, then every variable with its unit
QuantityFormulaVariables and units
Continuity (incompressible)Q = A·V; A1V1 = A2V2Q volume flow (m³/s); V mean velocity (m/s)
Bernoulli (along a streamline)P/(ρg) + V²/(2g) + z = constantSteady, incompressible, inviscid, no pump or turbine; each term in m of head
Energy equation (pipe systems)P1/γ + V1²/2g + z1 + hp = P2/γ + V2²/2g + z2 + ht + hLhp pump head; ht turbine head; hL head loss (m)
Momentum (steady control volume)ΣF = ρ·Q·(Vout − Vin)Vector equation; F (N); one inlet and one outlet
Pump powerPshaft = ρ·g·Q·hp/ηη pump efficiency; P (W)

Pipe flow

Pipe flow: formula, then every variable with its unit
QuantityFormulaVariables and units
Reynolds numberRe = ρ·V·D/μ = V·D/νD pipe inside diameter (m); laminar below about 2 300 in pipes
Hydraulic diameterDh = 4A/PwPw wetted perimeter (m); for non-circular ducts
Darcy–Weisbach head losshL = f·(L/D)·V²/(2g)f Darcy friction factor; L pipe length (m)
Laminar friction factorf = 64/ReFully developed laminar flow in a round pipe
Turbulent friction factor (Swamee–Jain)f = 0.25 / [log10(ε/(3.7D) + 5.74/Re0.9)]²ε roughness (m); explicit fit to Colebrook, within a few percent
Minor losseshm = K·V²/(2g)K loss coefficient of a fitting, valve or entrance

How to use this cheat sheet

Choose two points where you know the most (a free surface, a jet open to the atmosphere, a gauge) and write the energy equation between them. Atmospheric pressure cancels when both points are open to it.

Work in heads (metres or feet of fluid) for pipe systems; pressure terms become P/γ and every term then has the same unit.

Check the Reynolds number before you pick a friction factor. Laminar and turbulent flow use different formulas, and the Moody chart’s laminar line is f = 64/Re.

Example: Head loss and pressure drop in a water line

Given

  • Water flows at Q = 3.0 L/s through L = 40 m of straight, horizontal steel pipe, inside diameter D = 50 mm
  • Roughness ε = 0.045 mm (typical for commercial steel)
  • Water: ν = 1.0 × 10⁻⁶ m²/s and ρ = 998 kg/m³ (typical values near 20 °C); g = 9.81 m/s²

Find

  • The Reynolds number
  • The friction factor (Swamee–Jain)
  • The head loss and pressure drop

Solution

  1. Mean velocity from continuity.A = π(0.050)²/4 = 1.963 × 10^-3 m²; V = 0.0030/1.963 × 10^-3 = 1.528 m/s
  2. Reynolds number: well above 2 300, so the flow is turbulent.Re = V·D/ν = 1.528 × 0.050 / 1.0 × 10^-6 = 76 400
  3. Friction factor from Swamee–Jain with ε/D = 0.0009.f = 0.25 / [log10(0.0009/3.7 + 5.74/76 400^0.9)]² = 0.25 / (−3.324)² = 0.0226
  4. Darcy–Weisbach head loss.h_L = 0.0226 × (40/0.050) × 1.528²/(2 × 9.81) = 2.15 m
  5. Horizontal pipe, constant diameter: the pressure drop is ρ·g·h_L.Δp = 998 × 9.81 × 2.154 = 21 100 Pa

Answer: Re ≈ 76 400 (turbulent); f ≈ 0.0226; h_L ≈ 2.15 m; Δp ≈ 21.1 kPa.

Printable cheat sheet

The PDF is one US Letter page that also prints on A4 without cropping. The 2:3 PNG is the same sheet as an image, sized for a phone lock screen or a pin. Both are made from the formulas in the tables above, so they always match.

Fluid Mechanics Cheat Sheet: Properties · hydrostatics · continuity · Bernoulli · energy equation · pipe losses
Fluid Mechanics Cheat Sheet (PNG, 2:3)

Matching lessons and calculators

Learn where each formula comes from, then check your own numbers.

All engineering cheat sheets

Frequently asked questions

When can I use the Bernoulli equation?

Along a streamline in steady, incompressible flow with negligible friction and no pump or turbine between the two points. Once a pipe is long or has fittings, use the energy equation with head loss instead.

Darcy or Fanning friction factor?

This sheet uses the Darcy factor, which is four times the Fanning factor. The Moody chart and f = 64/Re are Darcy forms. Check which one a table or textbook uses before mixing them.

Where does the 2 300 limit come from?

It is a common engineering threshold for the start of transition in round pipes. Transition really spans a range, roughly 2 300 to 4 000, and depends on disturbances in the flow.

See also

More cheat sheets

Sources

  1. B. R. Munson, T. H. Okiishi, W. W. Huebsch, A. P. Rothmayer, Fundamentals of Fluid Mechanics, Wiley
  2. F. M. White, Fluid Mechanics, McGraw Hill
  3. P. K. Swamee, A. K. Jain, Explicit equations for pipe-flow problems (1976), Journal of the Hydraulics Division, ASCE

Last updated

COPLAIN AI PLATFORM

Generate yours automatically from your existing docs

Heading into manufacturing? Coplain turns engineering procedures into clear, audit-ready work instructions and job aids for the shop floor.

Generate yours automatically with Coplain →