The Reynolds Number

The Reynolds number Re = ρVD/μ compares the inertia of a moving fluid with its viscosity. In a pipe, flow is smooth and layered (laminar) when Re is below about 2300 and chaotic (turbulent) above about 4000. Which regime you are in decides almost every other fluid calculation, starting with the friction loss.

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What the Reynolds number measures

A moving fluid carries momentum, which tends to keep disturbances growing, and viscosity, which damps them out. Re is the ratio of the two: Re = ρVD/μ = VD/ν, where ν = μ/ρ is the kinematic viscosity. It has no units, so the same Re means the same flow pattern whatever the fluid or pipe size.

For a pipe, the length scale D is the inside diameter and V is the mean velocity, Q divided by the flow area. Other shapes use their own length: the hydraulic diameter 4A/P for a duct, the chord for a wing, the diameter for a sphere. Their critical values differ from the pipe values.

Laminar, transitional and turbulent flow

Below Re ≈ 2300, pipe flow is laminar: fluid moves in smooth layers, the velocity profile is a parabola, and friction loss is proportional to velocity.

Above Re ≈ 4000, flow is turbulent: eddies mix the fluid across the pipe, the profile is much flatter, and friction loss grows roughly with velocity squared. Between the two, flow can switch back and forth, and results there are uncertain.

These limits are typical values for ordinary pipes. Very smooth, vibration-free laboratory pipes have stayed laminar far above 2300, so treat the numbers as engineering guides, not physical constants. The next lesson, the Darcy–Weisbach equation, turns the regime into a pressure drop.

Dynamic and kinematic viscosity

Dynamic viscosity μ is in Pa·s; the centipoise (cP) equals 1 mPa·s. Kinematic viscosity ν = μ/ρ is in m²/s; the centistokes (cSt) equals 1 mm²/s. Oil data sheets usually give ν in cSt at 40 °C and 100 °C. Use whichever form you have, but do not mix them in one formula.

Viscosity depends strongly on temperature. Liquids thin out as they warm, while gases get slightly more viscous, so always use properties at the operating temperature.

Key formulas

Formulas used on this page, with the textbook each is cited from
FormulaExpressionWhereCited from
Reynolds numberRe = ρ·V·D / μ = V·D / νD = inside diameter, V = mean velocityWhite, Fluid Mechanics
Mean velocity in a full pipeV = Q / (π·D² / 4)Q = volumetric flow rateMunson et al., Fundamentals of Fluid Mechanics
Kinematic viscosityν = μ / ρ1 cSt = 10⁻⁶ m²/s, 1 cP = 10⁻³ Pa·sWhite, Fluid Mechanics
Hydraulic diameterD_h = 4·A / PA = flow area, P = wetted perimeter; D_h = D for a round pipeMunson et al., Fundamentals of Fluid Mechanics

Worked examples

Example: Flow regime in a hydraulic return line

Given

  • Hydraulic oil flows at 6 L/min through a line with a 12 mm bore.
  • The oil is an ISO VG 46 grade at 40 °C. The grade number is its nominal kinematic viscosity, so ν = 46 mm²/s = 46 × 10⁻⁶ m²/s.

Find

  • The Reynolds number and the flow regime.
  • The flow rate at which Re would reach 2300.

Solution

  1. Convert the flow rate to m³/s.Q = 6 L/min = 6 × 10⁻³ / 60 = 1.0 × 10⁻⁴ m³/s
  2. Find the flow area and mean velocity.A = π × 0.012² / 4 = 1.131 × 10⁻⁴ m², V = 1.0 × 10⁻⁴ / 1.131 × 10⁻⁴ = 0.884 m/s
  3. Use the kinematic form, since ν is given.Re = V·D / ν = 0.884 × 0.012 / 46 × 10⁻⁶ = 231
  4. Re is proportional to Q for a fixed pipe and fluid, so scale the flow to reach 2300.Q = 6 L/min × 2300 / 231 = 59.8 L/min

Answer: Re ≈ 231, well inside the laminar range. The line would stay laminar up to about 60 L/min at this oil temperature.

Example: Air in a ventilation duct

Given

  • Air flows at 5 m/s in a round duct with a 200 mm inside diameter.
  • Take ρ = 1.2 kg/m³ and μ = 1.8 × 10⁻⁵ Pa·s, typical handbook values for air near room temperature.

Find

  • The Reynolds number and the flow regime.
  • The velocity below which the flow would be laminar.

Solution

  1. Use the dynamic form, since ρ and μ are given.Re = ρ·V·D / μ = 1.2 × 5 × 0.2 / 1.8 × 10⁻⁵ = 66 700
  2. Re is far above 4000, so the flow is turbulent.66 700 > 4000
  3. Solve Re = 2300 for the velocity.V = 2300 × 1.8 × 10⁻⁵ / (1.2 × 0.2) = 0.173 m/s

Answer: Re ≈ 66 700, so the flow is turbulent. It would only be laminar below about 0.17 m/s, which is why nearly all duct and plant air flow is turbulent.

Common mistakes

In industry

Frequently asked questions

What Reynolds number is turbulent?

For flow in a round pipe, usually above about 4000. Below about 2300 it is laminar, and between the two it is transitional.

Does the Reynolds number have units?

No. ρVD/μ is dimensionless when consistent units are used, which is why it can compare flows of different fluids and sizes.

Why does a higher viscosity make flow laminar?

Viscosity damps the small disturbances that grow into turbulence. A larger μ lowers Re for the same velocity and pipe, so the damping wins.

How do I calculate it for a pipe quickly?

Use Coplain’s pipe pressure drop calculator, linked below. It reports Re and the regime along with the friction factor and pressure drop.

Keep learning

All Fluid Mechanics lessons · All engineering subjects

See also

Sources

  1. F. M. White, Fluid Mechanics, McGraw Hill
  2. B. R. Munson, T. H. Okiishi, W. W. Huebsch, A. P. Rothmayer, Fundamentals of Fluid Mechanics, Wiley
  3. ISO 3448, Industrial liquid lubricants — ISO viscosity classification, ISO

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