Example: Travel time of an automated guided vehicle
Given
- An automated guided vehicle (AGV) moves 30 m between two stations, starting and ending at rest.
- It accelerates at 0.5 m/s² to a top speed of 1.5 m/s, cruises, then brakes at 0.75 m/s².
Find
- The distance used by each phase.
- The total travel time.
Solution
- Acceleration phase, from v = v₀ + a·t and v² = v₀² + 2·a·s.
t₁ = 1.5 / 0.5 = 3.0 s, s₁ = 1.5² / (2 × 0.5) = 2.25 m - Braking phase, with the same equations and a = −0.75 m/s².
t₃ = 1.5 / 0.75 = 2.0 s, s₃ = 1.5² / (2 × 0.75) = 1.50 m - Cruise phase covers the rest of the distance at constant speed. It is positive, so the AGV does reach top speed.
s₂ = 30 − 2.25 − 1.50 = 26.25 m, t₂ = 26.25 / 1.5 = 17.5 s - Add the three phases.
t = 3.0 + 17.5 + 2.0 = 22.5 s
Answer: The AGV uses 2.25 m to speed up, 26.25 m cruising and 1.50 m to stop, for a travel time of 22.5 s. If the cruise distance had come out negative, the move would be a triangle profile that never reaches 1.5 m/s.